🤖 自动格式化代码 [skip ci]
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@@ -235,12 +235,14 @@ class ActionPlanner:
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recent_knowledge = conversation_info.knowledge_list[-3:]
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for i, knowledge_item in enumerate(recent_knowledge):
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if isinstance(knowledge_item, dict):
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query = knowledge_item.get('query', '未知查询')
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knowledge = knowledge_item.get('knowledge', '无知识内容')
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source = knowledge_item.get('source', '未知来源')
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query = knowledge_item.get("query", "未知查询")
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knowledge = knowledge_item.get("knowledge", "无知识内容")
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source = knowledge_item.get("source", "未知来源")
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# 只取知识内容的前 2000 个字,避免太长
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knowledge_snippet = knowledge[:2000] + "..." if len(knowledge) > 200 else knowledge
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knowledge_info_str += f"{i+1}. 关于 '{query}' 的知识 (来源: {source}):\n {knowledge_snippet}\n"
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knowledge_info_str += (
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f"{i + 1}. 关于 '{query}' 的知识 (来源: {source}):\n {knowledge_snippet}\n"
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)
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else:
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# 处理列表里不是字典的异常情况
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knowledge_info_str += f"{i + 1}. 发现一条格式不正确的知识记录。\n"
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@@ -138,7 +138,7 @@ class ReplyGenerator:
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goals_str = "- 目前没有明确对话目标\n" # 简化无目标情况
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# --- 新增:构建知识信息字符串 ---
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knowledge_info_str = "【供参考的相关知识和记忆】\n" # 稍微改下标题,表明是供参考
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knowledge_info_str = "【供参考的相关知识和记忆】\n" # 稍微改下标题,表明是供参考
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try:
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# 检查 conversation_info 是否有 knowledge_list 并且不为空
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if hasattr(conversation_info, "knowledge_list") and conversation_info.knowledge_list:
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@@ -158,7 +158,7 @@ class ReplyGenerator:
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knowledge_info_str += f"{i + 1}. 发现一条格式不正确的知识记录。\n"
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if not recent_knowledge:
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knowledge_info_str += "- 暂无。\n" # 更简洁的提示
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knowledge_info_str += "- 暂无。\n" # 更简洁的提示
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else:
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knowledge_info_str += "- 暂无。\n"
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