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@@ -231,15 +231,15 @@ class ActionPlanner:
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try:
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# 检查 conversation_info 是否有 knowledge_list 并且不为空
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if hasattr(conversation_info, "knowledge_list") and conversation_info.knowledge_list:
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# 最多只显示最近的 3 条知识,防止 Prompt 过长
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recent_knowledge = conversation_info.knowledge_list[-3:]
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# 最多只显示最近的 5 条知识,防止 Prompt 过长
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recent_knowledge = conversation_info.knowledge_list[-5:]
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for i, knowledge_item in enumerate(recent_knowledge):
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if isinstance(knowledge_item, dict):
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query = knowledge_item.get('query', '未知查询')
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knowledge = knowledge_item.get('knowledge', '无知识内容')
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source = knowledge_item.get('source', '未知来源')
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# 只取知识内容的前 2000 个字,避免太长
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knowledge_snippet = knowledge[:2000] + "..." if len(knowledge) > 200 else knowledge
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knowledge_snippet = knowledge[:2000] + "..." if len(knowledge) > 2000 else knowledge
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knowledge_info_str += f"{i+1}. 关于 '{query}' 的知识 (来源: {source}):\n {knowledge_snippet}\n"
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else:
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# 处理列表里不是字典的异常情况
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@@ -142,15 +142,15 @@ class ReplyGenerator:
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try:
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# 检查 conversation_info 是否有 knowledge_list 并且不为空
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if hasattr(conversation_info, "knowledge_list") and conversation_info.knowledge_list:
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# 最多只显示最近的 3 条知识
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recent_knowledge = conversation_info.knowledge_list[-3:]
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# 最多只显示最近的 5 条知识
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recent_knowledge = conversation_info.knowledge_list[-5:]
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for i, knowledge_item in enumerate(recent_knowledge):
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if isinstance(knowledge_item, dict):
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query = knowledge_item.get('query', '未知查询')
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knowledge = knowledge_item.get('knowledge', '无知识内容')
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source = knowledge_item.get('source', '未知来源')
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# 只取知识内容的前 150 个字
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knowledge_snippet = knowledge[:150] + "..." if len(knowledge) > 150 else knowledge
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knowledge_snippet = knowledge[:2000] + "..." if len(knowledge) > 2000 else knowledge
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knowledge_info_str += f"{i+1}. 关于 '{query}' (来源: {source}): {knowledge_snippet}\n" # 格式微调,更简洁
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else:
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knowledge_info_str += f"{i+1}. 发现一条格式不正确的知识记录。\n"
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